Given the sum and product of roots, we can find the quadratic equation using the formula above!
Using the formula: x² - (sum)x + (product) = 0
Substitute the values: x² - (-9)x + 20 = 0
Simplify: x² + 9x + 20 = 0
Final Answer: x² + 9x + 20 = 0
Using the formula: x² - (sum)x + (product) = 0
Substitute the values: x² - (5/3)x + 4 = 0
Multiply all terms by 3 to eliminate fraction: 3x² - 5x + 12 = 0
Final Answer: 3x² - 5x + 12 = 0
Using the formula: x² - (sum)x + (product) = 0
Substitute the values: x² - (-3/2)x + (-1) = 0
Simplify: x² + (3/2)x - 1 = 0
Multiply all terms by 2: 2x² + 3x - 2 = 0
Final Answer: 2x² + 3x - 2 = 0
Using the formula: x² - (sum)x + (product) = 0
Substitute the values: x² - [−(2−a)²]x + (a + 5)² = 0
Simplify: x² + (2−a)²x + (a + 5)² = 0
Final Answer: x² + (2−a)²x + (a + 5)² = 0
For any quadratic equation ax² + bx + c = 0:
Sum of roots = -b/a
Product of roots = c/a
Here, a = 1, b = 3, c = -28
Sum of roots = -b/a = -3/1 = -3
Product of roots = c/a = -28/1 = -28
Final Answer: Sum = -3, Product = -28
First, write in standard form: x² + 3x + 0 = 0
Here, a = 1, b = 3, c = 0
Sum of roots = -b/a = -3/1 = -3
Product of roots = c/a = 0/1 = 0
Final Answer: Sum = -3, Product = 0
First, rewrite the equation:
Multiply all terms by a²: 3 + a = 10a²
Rearrange: 10a² - a - 3 = 0
Here, a = 10, b = -1, c = -3
Sum of roots = -b/a = -(-1)/10 = 1/10
Product of roots = c/a = -3/10
Final Answer: Sum = 1/10, Product = -3/10
Here, a = 3, b = -1, c = -4
Sum of roots = -b/a = -(-1)/3 = 1/3
Product of roots = c/a = -4/3
Final Answer: Sum = 1/3, Product = -4/3
Enter sum and product of roots to generate a quadratic equation: